(7x+3)(2x^2-17x-9)=0

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Solution for (7x+3)(2x^2-17x-9)=0 equation: 


Simplifying
(7x + 3)(2x2 + -17x + -9) = 0

Reorder the terms:
(3 + 7x)(2x2 + -17x + -9) = 0

Reorder the terms:
(3 + 7x)(-9 + -17x + 2x2) = 0

Multiply (3 + 7x) * (-9 + -17x + 2x2)
(3(-9 + -17x + 2x2) + 7x * (-9 + -17x + 2x2)) = 0
((-9 * 3 + -17x * 3 + 2x2 * 3) + 7x * (-9 + -17x + 2x2)) = 0
((-27 + -51x + 6x2) + 7x * (-9 + -17x + 2x2)) = 0
(-27 + -51x + 6x2 + (-9 * 7x + -17x * 7x + 2x2 * 7x)) = 0
(-27 + -51x + 6x2 + (-63x + -119x2 + 14x3)) = 0

Reorder the terms:
(-27 + -51x + -63x + 6x2 + -119x2 + 14x3) = 0

Combine like terms: -51x + -63x = -114x
(-27 + -114x + 6x2 + -119x2 + 14x3) = 0

Combine like terms: 6x2 + -119x2 = -113x2
(-27 + -114x + -113x2 + 14x3) = 0

Solving
-27 + -114x + -113x2 + 14x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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